billyk
Guru
We've been having a long discussion in the thread "Are you a pusher or a puller?". A whole lotta words got slung around (including mine), without seeming to shed much light.
The thread filled up with chatter about various ways the alternating pedal pushes get balanced. It didn't ring true to me, but I realized I couldn't quite explain it.
Yesterday afternoon it finally stopped raining here in atmospheric-river land and I got a chance to do some riding tests. I wanted to see how much force it takes to counteract pedal steer, and figure out why my experience says "very little".
I first did a bunch of trials that weren't useful because I often ride no-hands and couldn't suppress the muscle-memory of that enough to do realistic push-pull tests.
Then I picked a hill (much) too steep for me to ride no-hands. I rode up it holding the bars with just one hand. There definitely was a push-pull going on, but it didn't seem to need much force compared to how hard I was pushing on the pedals (very hard). How can that be?
There are two pieces to the answer:
1) The handgrips are much further offset from the steering column than the pedals are (ignoring the length of the boom for the moment). On my Q the distance from steering column to the center of the hand-grips is 11.5 inches, and the center of the pedals are about 5.5 inches from the center of the BB. That gives your hands a larger lever arm by a factor of about 2.
That extra leverage means one could balance the torque of pedal-steer with _half_ the force being put into the pedals.
But considering how hard I was pushing to go uphill, what I was doing with my one hand didn't feel like half that.
2) The pedals are far out in front of the bars, on my Q about 28 inches. This turns out to be the main story (see attached diagram; you can read the fine print but it should be comprehensible just looking at the diagram):
The forward-directed off-center pedal push (vector c) can be decomposed into the two perpendicular vectors a and b, which combined give an equivalent force. Vector b is along the line from the steering axis to the pedal center; any force along this line points directly away from the axis and therefore has zero component around the steering axis: it does not contribute any rotation to it (no pedal steer from this).
(This is how you ride no-hands: push slightly outward along vector b.)
The much smaller vector a is the only thing giving pedal steer: its action is to rotate the BB around the steering axis.
Using numbers taken from my Q:
Boom length = 28 inches
Distance from the center of the pedals to the center of the BB = 5.5 inches
A bit of trigonometry (details on request) leads to angle Phi=11.1 degrees, with sin(Phi)=0.193.
That is the ratio a/c, namely the fraction of pedal force (c) that goes into pedal steer (a).
=> Pedal steer is about 19% as large as the pedal forward push due to this aspect of the geometry.
=> When you also include the handgrip distance factor of one-half as in (1) above, the pedal steer that needs to be counteracted by the arms is about 10% as large as the forward pedal force.
It's not nothing, but it is small. It's hardly noticeable in the both-hands pulling that gives more power when sprinting or climbing.
And regarding the push-pull debate in the earlier thread: Yes, you can balance pedal steer either by arm-pulling on the side that your foot is pushing, or arm-pushing on the opposite side. But this only works if you are not overall pulling to strengthen the force you are able to direct to the pedals, that is, if the only use of your arms is to counteract pedal steer. In that case you get no extra upper-body power.
If you ARE trying to use your upper body to gain power, then you need to pull with both hands, slightly alternating the pull from each arm: by about 10%. Like I said, in my experience it is hardly noticeable.
The thread filled up with chatter about various ways the alternating pedal pushes get balanced. It didn't ring true to me, but I realized I couldn't quite explain it.
Yesterday afternoon it finally stopped raining here in atmospheric-river land and I got a chance to do some riding tests. I wanted to see how much force it takes to counteract pedal steer, and figure out why my experience says "very little".
I first did a bunch of trials that weren't useful because I often ride no-hands and couldn't suppress the muscle-memory of that enough to do realistic push-pull tests.
Then I picked a hill (much) too steep for me to ride no-hands. I rode up it holding the bars with just one hand. There definitely was a push-pull going on, but it didn't seem to need much force compared to how hard I was pushing on the pedals (very hard). How can that be?
There are two pieces to the answer:
1) The handgrips are much further offset from the steering column than the pedals are (ignoring the length of the boom for the moment). On my Q the distance from steering column to the center of the hand-grips is 11.5 inches, and the center of the pedals are about 5.5 inches from the center of the BB. That gives your hands a larger lever arm by a factor of about 2.
That extra leverage means one could balance the torque of pedal-steer with _half_ the force being put into the pedals.
But considering how hard I was pushing to go uphill, what I was doing with my one hand didn't feel like half that.
2) The pedals are far out in front of the bars, on my Q about 28 inches. This turns out to be the main story (see attached diagram; you can read the fine print but it should be comprehensible just looking at the diagram):
The forward-directed off-center pedal push (vector c) can be decomposed into the two perpendicular vectors a and b, which combined give an equivalent force. Vector b is along the line from the steering axis to the pedal center; any force along this line points directly away from the axis and therefore has zero component around the steering axis: it does not contribute any rotation to it (no pedal steer from this).
(This is how you ride no-hands: push slightly outward along vector b.)
The much smaller vector a is the only thing giving pedal steer: its action is to rotate the BB around the steering axis.
Using numbers taken from my Q:
Boom length = 28 inches
Distance from the center of the pedals to the center of the BB = 5.5 inches
A bit of trigonometry (details on request) leads to angle Phi=11.1 degrees, with sin(Phi)=0.193.
That is the ratio a/c, namely the fraction of pedal force (c) that goes into pedal steer (a).
=> Pedal steer is about 19% as large as the pedal forward push due to this aspect of the geometry.
=> When you also include the handgrip distance factor of one-half as in (1) above, the pedal steer that needs to be counteracted by the arms is about 10% as large as the forward pedal force.
It's not nothing, but it is small. It's hardly noticeable in the both-hands pulling that gives more power when sprinting or climbing.
And regarding the push-pull debate in the earlier thread: Yes, you can balance pedal steer either by arm-pulling on the side that your foot is pushing, or arm-pushing on the opposite side. But this only works if you are not overall pulling to strengthen the force you are able to direct to the pedals, that is, if the only use of your arms is to counteract pedal steer. In that case you get no extra upper-body power.
If you ARE trying to use your upper body to gain power, then you need to pull with both hands, slightly alternating the pull from each arm: by about 10%. Like I said, in my experience it is hardly noticeable.
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